The first 5 terms in an arithmetic sequence is 4,2,0,-2,-4
Explanation:
The general form of an arithmetic sequence is
[tex]a(n)=a+(n-1)d[/tex]
where a denotes the first term of the sequence, d denotes the common difference.
Here a = 4 and d = -2
To determine the consecutive terms of the sequence, let us substitute the values for n.
To find the second term, substitute n = 2 in the formula [tex]a(n)=a+(n-1)d[/tex]
[tex]a(2)=4+(2-1)(-2)[/tex]
Simplifying,
[tex]a(2)=4-2=2[/tex]
Similarly,
For n = 3,
[tex]a(3)=4+(2)(-2)=0[/tex]
For n = 4,
[tex]a(4)=4+(4-1)(-2)\\a(4)=4+(3)(-2)\\a(4)=4-6\\a(4)=-2[/tex]
For n = 5,
[tex]a(5)=4+(5-1)(-2)\\a(5)=4+(4)(-2)\\a(5)=4-8\\a(5)=-4[/tex]
Thus, the first 5 terms of the arithmetic sequence is 4,2,0,-2,-4
