A seagull is flying upwards such that it's height h in feet above the sea is given by h=3t. At the same time, the height h in feet of a rock falling off a cliff above the sea after t seconds is given by h=-16+50. Find the approximate time it takes for the rock and the bird to be at the same height.

Respuesta :

Answer:

1.68 seconds

Step-by-step explanation:

The approximate time it takes for the rock and the bird to be at the same height is 1.68 seconds.

The height of the seagull above the sea is given by:

[tex]h=3t[/tex]

The height of a rock falling off a cliff above the sea is given by:

[tex]h=-16t^{2} +50[/tex]

What is a solution to the system of two equations?

A solution to the system of two equations is the value of the independent variable that satisfies both equations.

So, the approximate time it takes for the rock and the bird to be at the same height will be given by:

[tex]3t=-16t^{2} +50[/tex]

[tex]16t^{2} +3t-50=0[/tex]

[tex]t=\frac{-3+\sqrt{9-4*16*(-50)} }{2*16}[/tex]

[tex]t=1.68[/tex] seconds.

Thus, the approximate time it takes for the rock and the bird to be at the same height is 1.68 seconds.

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