The 76th term of the arithmetic sequence 17, 19, 21 is 167.
Arithmetic progression
An arithmetic progression or arithmetic sequence is a sequence of numbers such that the difference between the consecutive terms is constant. It is given by:
[tex]a_n=a_1+(n-1)d\\\\a_1=first\ term, d = common\ difference[/tex]
Given 17, 19, 21:
a = 17, d = 19 - 17 = 2
Hence:
[tex]a_{76}=17+(76-1)2=167[/tex]
The 76th term of the arithmetic sequence 17, 19, 21 is 167.
Find out more on Arithmetic progression at: https://brainly.com/question/6561461
