Respuesta :
Answer:CBr4
Explanation:As a general solubility rule: 'like dissolves like'
that is more polar compounds can easily dissolve in polar solvents while non-polar compound can easily dissolve in non polar solvents.
Carbon tetracholride, CCl4, is a non polar solvent and CBr4 is also non polar hence it dissolves easily in ccl4.
While the rest of the compounds mentioned above are polar in nature hence they wont dissolve easily in ccl4.
The following substances is more likely to dissolve in [tex]CCl_{4}[/tex] - [tex]CBr_{4}[/tex]
[tex]CCl_{4}[/tex] is a tetrahedral molecule that has a total dipole moment of zero. So [tex]CCl_{4}[/tex] is a non-polar solvent.
- As the like dissolve in like which means the same nature molecules dissolve in the same nature solvents
- the polar molecule dissolves in polar solvents and non-polar dissolves in non-polar solvents.
- CBr₄ is a non-polar solute that dissolves in a non-polar solvent.
- NaCl is an ionic compound, HBr HCl CH₃CH₂OH re polar, therefore, does not dissolve in CCl₄.
Thus, The following substances is more likely to dissolve in CCl₄ - CBr₄
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