A black mamba snake has a length of 3.12 m and a top speed of 3.24 m/s . Suppose a mongoose and a black mamba find themselves nose to nose. In an effort to escape, the snake accelerates at 2.52 m/s 2 from rest.
A. How much time does it take the snake to reach its top speed?
B. How far does the snake travel in that time?C. Has the tail of the snake gone past the mongoose or does the mongoose have a chance to catch the black mamba?

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zainsubhani zainsubhani · Answer 1 · 2020-02-12T05:40:16+01:00

Answer:

Part A:

Time taken by the snake to reach its top speed is 1.28571 sec.

Part B:

Snake travels 2.0828 m in that time

Part C:

Mongoose have a chance to catch the black mamba

Explanation:

Part A:

According to first equation of motion:

[tex]v_f=at+v_i[/tex]

v_f is top speed

v_i is initial or minimum speed

t is time

a is acceleration

[tex]3.24=(2.52)t+0\\t=1.28571 sec[/tex]

Time taken by the snake to reach its top speed is 1.28571 sec

Part B:

According to Second equation of motion:

[tex]S=v_it+\frac{1}{2}at^2[/tex]

v_i=0

[tex]S=0.5(2.52)(1.28571)^2\\S=2.0828 m[/tex]

Snake travels 2.0828 m in that time

Part C:

Distance covered by black mamba is 2.0828 m which is less than its length 3.12 m

2.0828 m<3.12 m

Mongoose have a chance to catch the black mamba