Answer:
The products are 4-bromo-2-hexene and 2-bromo-3-hexene
Explanation:
The reaction starts between terminal carbon of of of the double bonds and [tex]H^{+}[/tex]. After attaching [tex]H^{+}[/tex] to the carbon, one double bond disapears leaveing nearby CH positively charged. This intermediate is a resonance hybrid of two possible structures. Reaction of bromide at one of the carbons gives the 1,2-addition product and at the other carbon gives 1,4-addition product.
