A cylindrical shell of radius 7.00 cm and length 260 cm has its charge uniformly distributed on itscurved surface. The magnitude of the electric field at a point20.0 cm radially outward from its axis(measured from the midpoint of the shell) is 36.0 kN/C.(a) Use approximate relationships to find thenet charge on the shell.(b) Use approximate relationships to find theelectric field at a point 4.00 cm from theaxis,measured radiallyoutward from the midpoint of the shell.

Respuesta :

Answer:

a) [tex]Q_{enc}=1.06\times 10^{-3}\ C[/tex]

b) Since no charge is enclosed by the imaginary surface at the given radial distance so the electric field measured outward form the axis is also zero.

Explanation:

Given:

radius of the cylindrical shell, [tex]r=0.07\ m[/tex]

length of the cylindrical shell, [tex]h=2.6\ m[/tex]

magnitude of electric field at 20 cm from the axis, [tex]E=36000\ N.C^{-1}[/tex]

a)

[tex]\oint E.dA=\frac{Q_{enc}}{\epsilon_0}[/tex]

[tex]\Rightarrow \vert E\vert \times 2\pi.r'.h=\frac{Q_{enc}}{\epsilon_0}[/tex]

[tex]36000\times 2\pi\times 0.2\times 2.6\times 9\times 10^{-9}=Q_{enc}[/tex]

[tex]Q_{enc}=1.06\times 10^{-3}\ C[/tex]

b)

Given radial distance, [tex]r=0.04\ m[/tex]

[tex]\oint E.dA=\frac{Q_{enc}}{\epsilon_0}[/tex]

[tex]\Rightarrow \vert E\vert \times 2\pi.r'.h=\frac{Q_{enc}}{\epsilon_0}[/tex]

[tex]\frac{Q_{enc}}{\epsilon_0} =\vert E\vert\times 2\pi.r'.h[/tex]

[tex]\frac{Q_{enc}}{\esilon_0} =0[/tex]

Since no charge is enclosed by the imaginary surface at the given radial distance so the electric field measured outward form the axis is also zero.