Answer:
[tex]t=108.50s[/tex]
Explanation:
The ant is under an uniform motion. So, we get the time taken by the ant to cross the strip from the definition of speed:
[tex]v=\frac{x}{t}\\t=\frac{x}{v}[/tex]
In this case, we use the vertical speed of the ant ([tex]v_y=vsin\theta[/tex]), since the ant crosses the strip that is 34.2 cm wide (vertically). So:
[tex]t=\frac{y}{v_y}\\t=\frac{y}{vsin\theta}\\t=\frac{34.2cm}{0.4\frac{cm}{s}sin(52^\circ)}\\t=108.50s[/tex]
