Answer:
The atomic weight of the substance is 2.4837 X 10⁻³ amu
Explanation:
For a body-centered cubic structure, the edge length is given as
[tex]X = \frac{4}{\sqrt{3}} *R[/tex]
Given edge length in this problem is 287 pm
[tex]R = \frac{X*\sqrt{3}}{4} = \frac{287 pm*\sqrt{3}}{4} = 124.27 pm[/tex]
Volume of a sphere = [tex]\frac{4}{3}\pi R^3[/tex] = 1.333π*(124.27 X 10⁻¹²)³ = 5.206 X 10⁻³⁴ m³ X 10⁶ cm³ = 5.206 X 10⁻²⁸ cm³
Mass = density X volume
Mass = (7.92 g/cm³) *(5.206 X 10⁻²⁸ cm³) = 41.23 10⁻²⁸ g
1.66 x 10⁻²⁴g = 1 amu
41.23 10⁻²⁸ g = 2.4837 X 10⁻³ amu
Therefore, the atomic weight of the substance is 2.4837 X 10⁻³ amu
The study of a chemical is called chemistry.
The correct answer to the following question is [tex]2.487*10^{-3}[/tex]
The data is given in the question is as follows:-
The formula we used to get the weight is as follows:-
Mass = volume * density
[tex](7.92) *(5.06 * 10^{-28} ) = 41.23* 10^{-28} g1.66 * 10^{-24}g \\ 41.23* 10^{-28} g = 2.4837 * 10^{-3} amu[/tex]
Hence, the correct answer is [tex]2.487*10^{-3}[/tex]
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https://brainly.com/question/20293447
