Answer:
14.47 m
Explanation:
The horizontal and vertical components of water velocity
[tex]v_h = vcos\alpha = 15cos20^0 = 14.1 m/s[/tex]
[tex]v_v = vsin\alpha = 15sin^0 = 5.03 m/s[/tex]
Ignore air resistance, gravity acceleration g = -9.8 m/s2 is the only thing that affects vertical motion of water, we can use the following equation to calculate the time it takes for water to shoot up then come down and hit the ground at h = 0 m
[tex]h = v_vt + gt^2/2[/tex]
[tex]0 = 5.03t - 9.8t^2/2[/tex]
[tex]-4.9t^2 + 5.03t = 0[/tex]
[tex]t(5.03 - 4.9t) = 0[/tex]
[tex] t = 0, 5.03 - 4.9t = 0[/tex]
[tex]t = 5.03 / 4.9 = 1.03 s[/tex]
This is also the time for water to travel horizontally at the rate of 14.1 m/s. We can use this to calculate the horizontal distance
[tex]s = v_ht = 14.1*1.03 = 14.47 m[/tex]
