Rahul solved the equation 2(x – ) – 2 left-parenthesis x minus StartFraction 1 Over 8 EndFraction right-parenthesis minus StartFraction 3 Over 5 EndFraction x equals StartFraction 55 Over 4 EndFraction x = 2 left-parenthesis x minus StartFraction 1 Over 8 EndFraction right-parenthesis minus StartFraction 3 Over 5 EndFraction x equals StartFraction 55 Over 4 EndFraction . In which step did he use the addition property of equality?

Respuesta :

Rahul use addition property of equality in step 2.

Solution:

The image of the question is attached below.

Step 1:

[tex]$2 x-\frac{1}{4}-\frac{3}{5} x=\frac{55}{4}[/tex]

combine like terms together.

[tex]$2 x-\frac{3}{5} x-\frac{1}{4}=\frac{55}{4}[/tex]

To make the denominator same multiply and divide 2x by 5.

[tex]$\frac{10}{5} x-\frac{3}{5} x-\frac{1}{4}=\frac{55}{4}[/tex]  

Step 2:

[tex]$\frac{7}{5} x-\frac{1}{4}=\frac{55}{4}[/tex]

By addition property of equality, add [tex]\frac{1}{4}[/tex] on both side of the equation.

[tex]$\frac{7}{5} x-\frac{1}{4}+\frac{1}{4}=\frac{55}{4}+\frac{1}{4}[/tex]

Step 3:

[tex]$ \frac{7}{5} x=\frac{56}{4}[/tex]

Step 4:

Multiply by [tex]\frac{5}{7}[/tex] on both side of the equation.

[tex]x=10[/tex]

Hence Rahul use addition property of equality in step 2.

Ver imagen shilpa85475

Answer:

step 2

Step-by-step explanation:

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