Consider the reaction

H2(g) + 1 2 O2(g) → H2O(ℓ) + 286 kJ

How much H2 would have to be burned to yield America’s daily energy share of 260,000 kcal? (1 cal = 4.184 J)

1.) 1900 mol

2.) 3800 mol

3.) 7600 mol

4.) 1 mol

Respuesta :

Answer: The amount of hydrogen gas consumed is 3800 moles

Explanation:

We are given:

America's daily energy share = [tex]260,000kCal=2.6\times 10^{8}Cal[/tex]    (Conversion factor: 1 kCal = 1000 Cal)

Converting this into Joules, we use the conversion factor:

1 Cal = 4.184 J

So, [tex]2.6\tims 10^8Cal=(2.6\tims 10^8\times 4.184)J=1.088\times 10^9J=1.088\times 10^6kJ[/tex]

For the given chemical equation:

[tex]H_2(g)+\frac{1}{2}O_2(g)\rightarrow H_2O(l)+286kJ[/tex]

By Stoichiometry of the reaction:

286 kJ of energy is released, when 1 mole of hydrogen is consumed

So, [tex]1.088\times 10^6kJ[/tex] of energy will be released when [tex]\frac{1}{286}\times 1.088\times 10^6=3800mol[/tex] of hydrogen gas is consumed

Hence, the amount of hydrogen gas consumed is 3800 moles