contestada

A lead pellet is propelled upward vertically by an air rifle with an initial velocity of 14.8 m/s. Find the maximum height for the pellet.

Respuesta :

Answer:

h = 11.16[m]

Explanation:

In order to solve this problem we must use the following kinematics equation:

[tex]v_{f} ^{2}= v_{o} ^{2}-2*g*h\\where:\\v_{f} = final velocity = 0\\ v_{o} = initial velocity = 14.8 [m/s]\\g = gravity = 9.81[m/s^2]\\h = elevation [m]\\\\0 = 14.8^{2}-2*9.81*h\\ h=\frac{219.04}{2*9.81} \\h=11.16[m][/tex]

The key to solving this problem with the above equation is to recognize that the final velocity is zero, at the moment when it reaches maximum height.

Note: the sign of gravitational acceleration is negative because it is acting in the opposite direction to the pellet movement.