Water flows upward in a pipe oriented at 30 degrees. The mercury manometer readsh= 12 cm. Bothfluids are at 20◦C. What is the pressure lossp1−p2in the pipe (in Pascals)?

Respuesta :

Answer:

The pressure difference in the pipe is 2666 Pa.

Explanation:

Given that,

Height = 12 cm

Angle = 30°

We need to calculate the height

Using formula of height

[tex]h_{1}=2\tan30[/tex]

[tex]h_{1}=1.154\ m[/tex]

We need to calculate the pressure difference in the pipe

Using formula of pressure

[tex]P_{2}=P_{1}+\rho_{w}h-\rho_{Hg}h-\rho_{w}h_{1}[/tex]

[tex]P_{2}-P_{1}=\rho_{w}h-\rho_{Hg}h-\rho_{w}h_{1}[/tex]

Where, [tex]\rho_{Hg}[/tex] = density of mercury

[tex]\rho_{w}[/tex] = density of water

Put the value into the formula

[tex]P_{2}-P_{1}=(13600-1000)\times12\times10^{-2}+1000\times1.154[/tex]

[tex]P_{2}-P_{1}=2666\ Pa[/tex]

Hence, The pressure difference in the pipe is 2666 Pa.

Ver imagen CarliReifsteck