Answer:
The pressure difference in the pipe is 2666 Pa.
Explanation:
Given that,
Height = 12 cm
Angle = 30°
We need to calculate the height
Using formula of height
[tex]h_{1}=2\tan30[/tex]
[tex]h_{1}=1.154\ m[/tex]
We need to calculate the pressure difference in the pipe
Using formula of pressure
[tex]P_{2}=P_{1}+\rho_{w}h-\rho_{Hg}h-\rho_{w}h_{1}[/tex]
[tex]P_{2}-P_{1}=\rho_{w}h-\rho_{Hg}h-\rho_{w}h_{1}[/tex]
Where, [tex]\rho_{Hg}[/tex] = density of mercury
[tex]\rho_{w}[/tex] = density of water
Put the value into the formula
[tex]P_{2}-P_{1}=(13600-1000)\times12\times10^{-2}+1000\times1.154[/tex]
[tex]P_{2}-P_{1}=2666\ Pa[/tex]
Hence, The pressure difference in the pipe is 2666 Pa.