A taxi driver provides service in two zones of a city. Fares picked up in zone A will have destination in zone A with probability 0.65 or in zone B with probability 0.35. Fares picked up in zone B will have destinations in zone A with probability 0.45 or in zone B with probability 0.55. The driver's expected profit for a trip entirely in zone A is $7; for a trip entirely in zone B is $8; and for a trip that involves both zones is $12. Find the taxi drivers average profit per trip.

Respuesta :

Answer:

The taxi drivers average profit per trip is $9.50.

Step-by-step explanation:

The taxi driver provides services in Zone A and Zone B.

Let [tex]D_{A}[/tex] = destination is in Zone A and [tex]D_{B}[/tex] = destination is in Zone B.

Given:

The probabilities are:

[tex]P(D_{A}|A)=0.65\\P(D_{B}|A)=0.35\\P(D_{A}|B)=0.45\\P(D_{B}|B)=0.55[/tex]

The Expected profit are:

If the trip is entirely in Zone A the expected profit is, E (A - A) = $7.

If the trip is entirely in Zone B the expected profit is, E (B - B) = $8.

If the trip involves both the zones the expected profit is,

E (A - B) = E (B - A) = $12.

Determine the expected profit earned in Zone A as follows:

[tex]E(Profit\ in\ A)=E(A-A)\times P(D_{A}|A)+E(A-B)\times P(D_{A}|B)\\=(7\times 0.65)+(12\times0.35)\\=8.75[/tex]

Determine the expected profit earned in Zone B as follows:

[tex]E(Profit\ in\ B)=E(B-B)\times P(D_{B}|B)+E(B-A)\times P(D_{B}|A)\\=(8\times 0.45)+(12\times0.55)\\=10.20[/tex]

The total expected profit is:

[tex]E (Profit)=E(Profit\ in\ A)\times P(Zone A) + E(Profit\ in\ B)\times P(Zone B)\\=(8.75\times0.50)+(10.20\times 0.50)\\=9.475\\\approx9.50[/tex]

Thus, the taxi drivers average profit per trip is $9.50.