Respuesta :
Answer:
Q' = 115.2 KJ
Explanation:
Given that
Current I = 10 A
Voltage = 120 V
Time t= 120 s
The energy supplied Q= V I t
Q= 10 x 120 x 120 J
Q= 144 x 1000 J
Q= 144 KJ
The change in the energy ΔEngg = 28.8 kJ
By using energy conservation
Q= Q' + ΔEngg
Q'=Wasted energy
Now by putting the values in the above equation
144 = Q' + 28.8 KJ
Q' = 115.2 KJ
Therefore the waste energy will be 115 kJ.
The amount of energy wasted in the process is Q' = 115.2 KJ
Calculation of the amount of energy wasted:
Since the heater used a current i.e. I =10 A for a voltage i.e. V = 120 volts in a time i.e. t = 120 s and there is the change in energy of the new egg and it is in raw form that provided by ΔEngg = 28.8 kJ.
So,
The energy supplied should be determined by multiplying the current, voltage, and time.
Q= 10 x 120 x 120 J
Q= 144 x 1000 J
Q= 144 KJ
Now here we used energy conservation for determining the wasted energy
So, Q' represents the energy wasted.
Now
144 = Q' + 28.8 KJ
Q' = 115.2 KJ
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