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In a certain residential suburb, 60% of all households get Internet service from the local cable company, 80% get television service from that company, and 50% get both services from that company. Select a household at random. Use three decimals. a.) What is the probability that it gets at least one of these two services from the company? Lethousehold with Internet service H teens = H2 What is the probability that t gets enactly one of these services from probability that it gets exactly one of these services from the company?

Respuesta :

adelekeademolu

Answer:

a) 0.900

b) 0.400

Step-by-step explanation:

Let I = households getting internet

T = households getting television

Then I = 60%

and T = 80%

[tex]I\cap T = 50\%[/tex] (Households that get both services)

a) Households getting at least one service, [tex]I\cup T = I + T - I\cap T= 60+80-50 =90\%=0.900[/tex]

b) Those getting internet only = [tex]I - I\cap T = 60 - 50 = 10\% = 0.1 [/tex]

Those getting television only = [tex]T - I\cap T = 80- 50=30\%=0.3[/tex]

Probability of getting exactly one service = 0.1 + 0.3 = 0.400

abiolataiwo2015

The probability that it gets at least one of these two services from the company is 90% and the probability that it gets exactly one of these services from the company is 40%.

Probability

a. Probability

P(Internet service) = 60%

P(Television service) = 80%

P(Internet &Television service) = 50%

P(I or T) = P(I) + PT) - P(I&T)

P(I or T)= 60 + 80 - 50

P(I or T)= 90%

b. Internet only = 60%-50%

Internet only=10%

Television only = 80%-50%

Television only=30%

Probability of exactly one service = 10%+ 30%

Probability of exactly one service =40%

Inconclusion the probability that it gets at least one of these two services from the company is 90% and the probability that it gets exactly one of these services from the company is 40%.

Learn more about probability here:https://brainly.com/question/24756209

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