Answer:
Option d All unique elements in oldList NOT including any repeats of elements.
Explanation:
Given the function isPartOf() that will check if the input item is found in the input list. Therefore if we run the following code segment
FOR EACH item IN oldList{
IF (NOT IsPartOf (newList, item))
{ APPEND (newList, item) }
}
the expression NOT IsPartOf (newList, item) will be evaluated to true if it encounter the first occurrence of a element and append the item to the newList. The repeat element will always be evaluated to False and therefore the repeat element won't be appended to the newList.
At the end, the newList will hold all the unique elements in oldList which doesn't include any repeats of elements.