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The total attendance at a school play was 1250.the cost of tickets was $6.00 for students and $7.50 for adults.The school drama club had a revenue total of $8362.50. How many of each ticket was sold for the play?

Respuesta :

Number of tickets sold to adults: 575

Number of tickets sold to students: 675

Step-by-step explanation:

To solve the problem, let's call:

A = the number of adults

S = the number of students

We know that the total attendance was 1250, so:

[tex]A+S=1250[/tex] (1)

Also we know that the cost of ticket was:

$6.00 per student

$7.50 per adult

And the total revenue was $8362.50

So we can write:

[tex]6.00S+7.50A=8362.50[/tex] (2)

Where [tex]6.00S[/tex] represents the revenue from students and [tex]7.50A[/tex] the revenue from adults.

So we have two equations in two variables, A and S. Multiplying eq.(1) by 6 we get

[tex]6A+6S=7500[/tex]

Dividing eq.(2) by this last equation, we get

[tex]1.50A=862.5[/tex]

From which we find

[tex]A=\frac{862.5}{1.50}=575[/tex]

And substituting into eq.(1),

[tex]575+S=1250\\S=1250-575=675[/tex]

Therefore:

Number of tickets sold to adults: 575

Number of tickets sold to students: 675

Learn more about systems of equations:

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Answer:

I think it’s C

67-a

Step-by-step explanation: