Answer:
Explanation:
Given
Object is thrown with a velocity of [tex]u=9\ m/s[/tex]
Acceleration due to gravity is -g (i.e. acting downward)
Vertical distance traveled by object is given by
[tex]v^2-u^2=2as[/tex]
where v=final velocity
u=initial velocity
a=acceleration
s=displacement
at maximum height final velocity is zero
[tex]0-(9)^2=2\times (-g)\times (s)[/tex]
[tex]s=\frac{81}{2g}=\frac{40.5}{g}\ m[/tex]
time taken to reach maximum height
using
v=u+at
0=9-gt
[tex]t=\frac{9}{g}\ s[/tex]
