A 7-ft tall steel cylinder has a cross-sectional area of 15 ft2. At the bottom, with a height of 2 ft, is liquid water, on top of which is a 4-ft-high layer of engine oil, see Fig P1.43. The engine oil surface is exposed to atmospheric air at 14.7 psia. What is the highest pressure in the water?

Respuesta :

Answer:

[tex]P=17.01 lbf/in^{2}[/tex]

Explanation:

the diagram is depict on the attached diagram.

The total pressure is the sum of the pressure in the two liquid and the atmospheric pressure. this can be expressed as

[tex]P=P_{atm} +P_{liquid}.\\[/tex]

the pressure of the liquid is expressed as

[tex]P_{liquid}=P_{water} +P_{oil}\\[/tex]

The pressure of the liquid is express as the product of the density,gravity and height

[tex]P_{water}=phg\\[/tex]

the density of water is 62.2lbm/ft^3 and the density of engine oil is 52.66lbm/ft^3

Hence we can compute the pressure as

[tex]P=14.7 +[(62.2*2) +(52.66*4) ]\frac{32.174}{144*32.174}\\P=14.7 +[(62.2*2) +(52.66*4) *0.0069 \\P=17.01 lbf/in^{2}[/tex]

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