Respuesta :
Answer:
The the maximum capillary rise of water between two vertical glass plates is 9.79 cm
The the maximum capillary rise of mercury between two vertical glass plates is -2.77 cm
Explanation:
Given that,
Distance = 0.15 mm
Suppose, The surface tension of water is 72 dynes/cm at 25°C for pure water and perfectly clean glass, the angle of contact is 0°.
(a). We need to calculate the maximum capillary rise of water between two vertical glass plates
Using formula of rise of liquid in capillary tube
[tex]h=\dfrac{2S\cos\theta}{r\rho g}[/tex]
Put the value into the formula
[tex]h=\dfrac{2\times72\cos0}{0.015\times1\times980}[/tex]
[tex]h=9.79\ cm[/tex]
(b). If the same plates, now spaced 0.20 mm apart, are in mercury
The density of mercury is 13.6 g/cm³, the angle of contact of mercury with glass is 139°, and the surface tension of mercury is 490 dyne/cm and g = 980 cm/s².
We need to calculate the minimum capillary drop
[tex]h=\dfrac{2\times490\cos(139)}{0.02\times13.6\times980}[/tex]
[tex]h=-2.77\ cm[/tex]
Hence, The the maximum capillary rise of water between two vertical glass plates is 9.79 cm
The the maximum capillary rise of mercury between two vertical glass plates is -2.77 cm
