To solve this problem we will apply the concept related to the kinetic energy of a system. This can be defined from the main equation of kinetic energy, equivalent to half the product of mass and the squared velocity. As energy is conserved, the sum of the total energy before the explosion will be equal at the end of the explosion. Mathematically this is,
[tex]KE = \frac{1}{2} \sum (mv^2)[/tex]
[tex]KE = \frac{1}{2}[6.9*2.8^2 + 5.4*3.9^2][/tex]
[tex]KE = 68.11J[/tex]
Therefore the total kinetic energy of the two mass is equal to 68.11J
After the collision, the total kinetic energy of the two-mass system will be "68.115 J".
A collision where there would be no overall expenditure of kinetic energy (K.E) throughout the systems as nothing more than a consequence of the impact, is considered as Elastic collision.
According to the question,
Mass of object, m₁ = 6.9 kg
m₂ = 5.4 kg
Velocity of object, v₁ = 2.8 m/s
v₂ = 3.9 m/s
Now,
After collision, the Kinetic energy will be:
= [tex]\frac{1}{2}[/tex] m₁v₁ + [tex]\frac{1}{2}[/tex] m₂v₂
By substituting the values, we get
= [tex]\frac{1}{2}[/tex] × 6.9 × (2.8)² + [tex]\frac{1}{2}[/tex] × 5.8 × (3.9)²
= [tex]\frac{1}{2}[/tex] × 6.9 × 7.84 + [tex]\frac{1}{2}[/tex] × 5.8 × 15.21
= [tex]\frac{1}{2}[/tex] × 54.096 + [tex]\frac{1}{2}[/tex] × 88.218
= 68.115 J
Thus the response above is correct.
Find out more information about collision here:
https://brainly.com/question/7694106
