The rectangle below has an area of 14x^4+6x^214x 4 +6x 2 14, x, start superscript, 4, end superscript, plus, 6, x, squared. The width of the rectangle is equal to the greatest common monomial factor of 14x^414x 4 14, x, start superscript, 4, end superscript and 6x^26x 2 6, x, squared. What is the length and width of the rectangle?

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Answer:

Width of rectangle = [tex]2x^{2}[/tex]

length of rectangle = [tex]7x^{2} +3[/tex]

Step-by-step explanation:

Area = [tex]14x^{4}+6x^{2}[/tex]

The greatest common monomial factor is that factor that [tex]14x^{4}[/tex] and [tex]6x^{2}[/tex] will divide without leaving a remainder.

[tex]14x^{4} = 2*7*x*x*x*x\\6x^{2} = 2*3*x*x[/tex]

The common factors are 2, x and x

Therefore, greatest common factor = [tex]2*x*x=2x^{2}[/tex]

Width of rectangle = Greatest common factor = [tex]2x^{2}[/tex]

Area of a rectangle = length * breadth

[tex]length=\frac{area}{width}=\frac{14x^{4}+6x^{2} }{2x^{2} } \\\\ length = \frac{14x^{4}}{2x^{2}} +\frac{6x^{2} }{2x^{2} } \\\\length=7x^{2} +3[/tex]

Length of rectangle = [tex]7x^{2} +3[/tex]

Area of rectangle is the product of length and width.

Length is [tex]7x^{2} +3[/tex]  and width is [tex]2x^{2}[/tex].

Since, Area of rectangle is given that [tex]14x^{4}+6x^{2}[/tex]

Area of rectangle =  [tex]14x^{4}+6x^{2}[/tex]

Greatest Common Monomial Factor is a factor which can be take common in each term of a given polynomial.

Now, we have to find Monomial Factor of [tex]14x^{4}+6x^{2}[/tex]

We observe that, [tex]2x^{2}[/tex] is common in both term of given polynomial.

         [tex]14x^{4}+6x^{2}=2x^{2} (7x^{2} +3)[/tex]

So, Common Monomial Factor is [tex]2x^{2}[/tex]

Since, width of the rectangle is equal to the greatest common monomial factor.

Thus, width of rectangle = [tex]2x^{2}[/tex]

[tex]Area = length*width\\\\length=\frac{Area}{width} \\\\length=\frac{14x^{4}+6x^{2} }{2x^{2} } =\frac{2x^{2} (7x^{2} +3)}{2x^{2} } \\\\length=7x^{2} +3[/tex]

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