Penelope is raising money for a school trip by selling bags of chips and fruit snacks. The price of each bag of chips is $1.75 and the price of each fruit snack is $1.50. Yesterday Penelope made $42.50 and sold 15 more bags of chips than fruit snacks. Determine the number of bags of chips sold and the number of fruit snacks sold

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Answer:

The number of bags of chips sold was 20 and the number of fruit snacks sold was 5

Step-by-step explanation:

Let

x ---> the number of bags of chips sold

y ---> the number of fruit snacks sold

we know that

Penelope made $42.50

so

[tex]1.75x+1.50y=42.50[/tex] ----> equation A

Penelope sold 15 more bags of chips than fruit snacks.

[tex]x=y+15[/tex] ----> equation B

substitute equation B in equation A

[tex]1.75(y+15)+1.50y=42.50[/tex]

solve for y

[tex]1.75y+26.25+1.50y=42.50\\3.25y=16.25\\y=5[/tex]

Find the value of x

[tex]x=5+15=20[/tex]

therefore

The number of bags of chips sold was 20 and the number of fruit snacks sold was 5

The number of bags of chips sold was 20 and the number of fruit snacks sold was 5.

Given that,

  • The price of each bag of chips is $1.75 and the price of each fruit snack is $1.50.
  • Yesterday Penelope made $42.50 and sold 15 more bags of chips than fruit snacks.
  • Here we assume x be the number of bags of chips sold  and y be the number of fruit snacks sold.

Based on the above information, the calculation is as follows:

1.75x + 1.50y = 42.50

x = y + 15

Now put x value to the above equation

1.75(y + 15) + 1.50y = 42.50

1.75y  + 26.25 + 1.50y = 42.50

3.25y = 16.25

y = 5

So, x = 5 + 15 = 20

Learn more: brainly.com/question/17429689