If a wooden block of 1.93 kg is being pushed with a force of 4.57 Newtons in the horizontal direction. The box is on a horizontal surface that has static friction coefficient of 0.43 and a kinetic friction coefficient of 0.26. What is the size of the frictional force the block is experiencing if the block is not moving?

Respuesta :

Answer:

Explanation:

Given

mass of block [tex]m=1.93\ kg[/tex]

Force acting on the block [tex]F=4.57\ N[/tex]

Coefficient of static Friction [tex]\mu _s=0.43[/tex]

Coefficient of kinetic Friction [tex]\mu _k=0.26[/tex]

If the block is not moving then static friction is opposing the force acting

Static friction[tex]=\mu _sN[/tex]

where N=Normal reaction

[tex]N=mg[/tex]

[tex]f_s=0.43\times 1.93\times 9.8=8.133\ N[/tex]

Static Friction will auto adjust itself according to the applied force .

So [tex]static\ friction =Applied\ friction=4.57\ N[/tex]