Respuesta :
Answer:
(a). The resistance of this resistor is 87.72 Ω.
(b). The current is 0.147 A.
(c). The potential difference across the terminals of the battery is 40 volt.
Explanation:
Given that,
Voltage = 1.50 V
Current = 17.1 mA
(a). We need to calculate the resistance of this resistor
Using ohm's law
[tex]V=IR[/tex]
[tex]R=\dfrac{V}{I}[/tex]
Put the value into the formula
[tex]R=\dfrac{1.50}{17.1\times10^{-3}}[/tex]
[tex]R=87.72\ \Omega[/tex]
(b). If you now place the resistor across the terminals of a 12.9 V car battery having no internal resistance,
We need to calculate the current
Using ohm's law
[tex]V=IR[/tex]
[tex]I=\dfrac{V}{R}[/tex]
Put the value into the formula
[tex]I=\dfrac{12.9}{87.72}[/tex]
[tex]I=0.147\ A[/tex]
(c). The resistor across the terminals of an unknown battery of negligible internal resistance and measure a current of 0.456 A flowing through it.
We need to calculate the potential difference across the terminals of the battery
Using formula of potential difference
[tex]V=IR[/tex]
Put the value into the formula
[tex]V=0.456\times87.72[/tex]
[tex]V=40\ volt[/tex]
Hence, (a). The resistance of this resistor is 87.72 Ω.
(b). The current is 0.147 A.
(c). The potential difference across the terminals of the battery is 40 volt.
