It takes 4.37 J of heat to raise the temperature of Object A by 1°C, and 2.88 J to raise the temperature of Object B by 1°C. Suppose A and B are brought into contact. A is initially hotter. A is seen to cool down by 6.3°C . How would you calculate the rise in temperature of B?
Set the math up. But don't do any of it. Just leave your answer as a math expression. Also, be sure your answer includes all the correct unit symbols.

Object A hotter than B and they have direct contact that allows heat to transferred conductively. The law of conservation of energy states that energy cannot be destroyed or created. In this case, the energy that objects A loses can only go to object B.

Assuming that the mass of both objects is the same, to find the energy transferred you have to multiply the heat capacity with the degrees of temperature increases/decrease. The calculation will be:

Energy lost by A = Energy gained by B

A heat capacity* A lost temperature= B heat capacity * B gained temperature

4.37J/°C * 6.3°C= 2.88 J * Tb

Tb= (4.37 J/°C * 6.3 °C) / 2.88J

Tb= 9.56 °C

okpalawalter8 okpalawalter8 · Answer 2 · 2021-09-04T01:29:38+02:00

We have that the rise in temperature of B is

[tex]\triangle B=9.6 \textdegree[/tex]

From the Question we are told that

Heat capacity = 4.37 J

Temperature Object A

2.88 J to raise the temperature of Object B by 1°C

[tex]\triangle A =6.3 \textdegree C[/tex]

Generally

Heat lost by A = heat capacity of A *[tex]\triangle A[/tex]

[tex]Heat\ lost\ by A = 4.37 * 6.3[/tex]

[tex]Heat\ lost by A= 27.5 J[/tex]

Where

Heat lost by A=Heat gained by B

[tex]Heat\ gained\ by \B = heat\ capacity B * \triangle B[/tex]

[tex]\triangle B=\frac{27.5}{2.88}[/tex]

[tex]\triangle B=9.6 \textdegree[/tex]

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