Answer:
548s = t
Explanation:
A first-order reaction has as general equation:
[tex]ln \frac{[A]_t}{[A]_0} = -kt[/tex]
Where [tex][A]_t[/tex] is the concentration of the reactant in the time t, [tex][A]_0[/tex] is the initial concentration of the reactant, k is rate constant and t is time. Replacing with values of the problem:
[tex]ln \frac{8.30x10^-3}{4.30x10^-2} = -3.00x10^-3s^-1*t[/tex]
-1.65 = -3.00x10⁻³s⁻¹×t
548s = t
I hope it helps!
