Answer:
P(X ≤ 45)=0.2643
Step-by-step explanation:
We were given that the random variable X is normally distributed, with mean
μ=50 and standard deviation σ=8.
We want to compute the probability, P(X ≤ 45).
First, we need to calculate the z-score of X=45 using
[tex]Z=\frac{X-\mu}{\sigma}[/tex]
We substitute these values to get:
[tex]Z=\frac{45-50}{8}[/tex]
[tex]Z=\frac{-5}{8} =-0.63[/tex]
We now read area that corresponds to -0.63 in the standard normal distribution table.
This gives us P(X ≤ 45)=0.2643
