Answer:
0.118 is the probability someone will spend no more than 30 minutes reading online national news reports.
Step-by-step explanation:
We are given the following information in the question:
Mean, μ = 49 minutes
Standard Deviation, σ = 16 minutes
We are given that the distribution of time an individual reads is a bell shaped distribution that is a normal distribution.
Formula:
[tex]z_{score} = \displaystyle\frac{x-\mu}{\sigma}[/tex]
P(no more than 30 minutes)
[tex]P( x \leq 610) = P( z \leq \displaystyle\frac{30 - 49}{16}) = P(z \leq -1.1875)[/tex]
Calculation the value from standard normal z table, we have,
[tex]P(x \leq 30) = 0.118 = 11.8\%[/tex]
0.118 is the probability someone will spend no more than 30 minutes reading online national news reports.
