Answer:
16 mg of water can be produced by 7.1×10⁻³ g of CH₄
Explanation:
This is the reaction:
CH₄ + 2O₂ → CO₂ + 2H₂O
In a combustion, oxgen is a reactant with another compound, and the products are always water and carbon dioxide
1 mol of methane can produce 2 moles of water. Ratio is 1:2
If we convert the mass to moles → 7.1×10⁻³ g . 1 mol/ 16g = 4.43×10⁻⁴ mol
In this reaction I would produce the double of moles I have from methane, so If I have 4.43×10⁻⁴ moles of methane I would produce 8.87×10⁻⁴ moles of water.
What mass of water, corresponds to 8.87×10⁻⁴ moles?
8.87×10⁻⁴ mol . 18g / 1mol = 0.016 g which is actually the same as 16 mg
