Answer: 5.22m
Step-by-step explanation:
Using the rule of similar triangles where the the side lengths of two similar triangles are proportional
Parameters :
Tree height = t
Raul's height = 1.53m
Height of Raul's shadow = 8.73m
Total length of tree shadow = distance walked along tree shadow+ distance left to the end of tree shadow, Therefore,
Total length of tree shadow = 21.11 + 8.73 = 29.84m
Therefore,
Raul's ratio = tree's ratio
Raul's height : Raul's shadow = tree height : tree shadow
1.53 : 8.73 = t : 29.84
1.53/8.73 = t/29.84
1.53 × 29.84 = 8.73× t
t = 45.6552 / 8.73
t = 5.22m
Answer:
h = 5.23 m
Therefore, the tree is 5.23 m tall
Step-by-step explanation:
The question can be represented by the sketch in the attached image.
Where BE is the height of raul and CD is the tree's height (h)
Triangle ABE and ACD are both similar triangle.
And the ratio of their sides are equal
So,
BE/AE = CD/AD .....1
From the sketch,
BE = 1.53m
AE = 8.73m
CD = h
AD = 8.73 + 21.11m = 29.84m
Substituting into equation 1
1.53/8.73 = h/29.84
h = 29.84 × 1.53/8.73
h = 5.23 m
Therefore, the tree is 5.23 m tall
