Answer:
61.6 g of CO₂ were produced
Explanation:
Let's think the combustion
C + O₂ → CO₂
First of all we determine the moles:
16.8 g . 1mol / 12 g = 1.4 moles
As the question states the oxygen is remained unreacted, the oxygen is the reactant in excess, so the limiting is the C.
1 mol of C produces 1 mol of CO₂, so 1.4 moles in the reactant will produce the same amount products.
We convert the moles to mass.
1.4 mol . 44 g / 1mol = 61.6 g