Answer:
'Earth is the size of a tip of a ballpoint pen about 15 m away from the sun, is the correct answer.
Explanation
Radius of sun = 7 x 10^8 m
Radius of the earth = 6.37 x 10^6 m
Radius of grapefruit = 7.6 x 10^-2 m
Since sun is the size of a grapefruit.
So, our scale = (7.6 x 10^-2) / (7 x 10^8) = 10^-10
Means the scale is approximately, 1:10^-10
So, size of earth = 6.37 x 10^6 x 10^-10 = 6.37 x 10^-4 m (Size of ballpoint)
As we know that the distance between the sun and the earth = 14.9 x 10^10 m
So, in our scale, distance between the sun and the earth = 14.9 x 10^10 x 10^-10 = 14.9 m
which is approximately 15 meters.
Answer:
Earth is the size of a ball point about 15 meters away from the Sun.
Explanation:
Given
D_grapefruit = 0.15m
D_Sun = 1.3927*10⁹m
D_Earth = 12742000 m
D_golf ball = 0.04267 m
Distance between the Sun and the Earth = d = 149.6*10⁹ m
We get the relation between the grapefruit and the Sun as follows
E = D_grapefruit / D_Sun = 0.15m / 1.3927*10⁹m = 1.077*10⁻¹⁰
then
we have
D = d*E = (149.6*10⁹ m)*(1.077*10⁻¹⁰) ≈ 15 m
On the other hand
D_golf ball < D_ball point
0.04267 m < 0.147 m
then
D_golf ball / D_Earth = 0.04267 m / 12742000 m = 3.35*10⁻⁹
D_ball point / D_Earth = 0.147 m / 12742000 m = 1.15*10⁻⁸
As 3.35*10⁻⁹ < 1.15*10⁻⁸
we can say that 1.077*10⁻¹⁰ is closer to 1.077*10⁻¹⁰
finally
Earth is the size of a ball point about 15 meters away from the Sun.
