Answer:
V = 3712 m³
Step-by-step explanation:
The volume (V) of a pyramid is calculated as
V = [tex]\frac{1}{3}[/tex] Bh ( B is the area of the base and h the perpendicular height )
To find h use Pythagoras' identity
Where the slant height is the hypotenuse and the legs are h and half the width of the rectangular base, then
h² + 12² = 20², that is
h² + 144 = 400 ( subtract 144 from both sides )
h² = 256 ( take the square root of both sides )
h = [tex]\sqrt{256}[/tex] = 16
Thus
B = 29 × 24 = 696 m² and h = 16, hence
V = [tex]\frac{1}{3}[/tex] × 696 × 16 = 232 × 16 = 3712 m³
