Step-by-step explanation:
by using y=uv derivative formula and stationary mean y' = 0
y' = 3(x–2)⁴ + 3(3x–1)(x–2)³ = 0
cancel 3 and factorize
(x–2+3x–1)(x–2)³ = 0
x = ¾ or x = 2
we got point [tex]\left(\frac{3}{4},\frac{5^5}{4^5}\right)[/tex] and (2,0)