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On the graph of f(x) = sin x and the interval (-2pi,0), for what value of x does f(x) achieve a minimum? Choose all
answers that apply.

Respuesta :

ghanami

Answer:

x = -pi/2

Step-by-step explanation:

hello :

f(x)=sin x     x⋲(-2pi,0)

the derivate for f is : f'(x) = cosx

f(x) achieve a minimum when : f'(x) =0

cosx = 0  genral solution is :

x = pi/2 +kpi    .. k in Z

but :  x⋲(-2pi,0) so : x = -pi/2.....(k = -1)

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