completing the square:
find the value of c that completes the square.

1.) x[tex]x^{2} +6x+c[/tex]
2.) [tex]x^{2} -34x+c[/tex]
3.) [tex]x^{2} -\frac{25}{13} x+c[/tex]

Respuesta :

Answer:

Step-by-step explanation:

Key to this method is remembering that

[tex](a+b)^2 = a^2 + 2ab + b^2[/tex]

So, if you divide the coefficient of x by 2 and square it, that will complete the square. With that in mind, things are easy.

6/2 = 3, so add [tex]3^2 = 9[/tex]

[tex]x^2+6x+9 = (x+3)^2[/tex]

So, c=9

Similarly, for the other two,

[tex]c = (\frac{-34}{2} )^2 = (-17)^2 = 289[/tex]

You don't really have to worry about the sign, since squaring will always make it positive

[tex](\frac{25}{13}) ^2 = \frac{625}{169}[/tex]