Answer: 5.095m
Step-by-step explanation:
We first calculate the net force acting on the car
FN = Forward Force - Resistive Force
FN = 3 600 - 3350 = 250N
ACCORDING TO NEWTON'S SECOND LAW ACCELERATION IS GIVEN BY:
a = Fnet/m
=250N/5.2*10kg = 4.8077m/s^2
Since V = at
t = v/a ...... 1
Equation of motion for the car;
S =ut + 1/2at^2
Where u = initial velocity for the car is zero
U=0
S=1/2at^2 ...... 2
Substitute to value of t in equation 1 into equation 2
S = 1/2 a(v/a)^2 = v^2/2a
= 7^2/2*4.8077=49/9.6154 = 5.095m
The car will travel for 5.095m
