Answer:
3.83 x 10^25 molecules
Explanation:
You first start off with 5100 grams. Then you use the molar mass to cancel out the grams and convert to moles ( 5100g/ 80.063 gmol). You would then be left with 63.69 mols of SO3. But since it asks for molecules, you would need to multiply this value by Avogadro's number (6.022 X 10^23) in order to cancel out the mols unit and end in amount of molecules.
From Avogadro's hypothesis, we understood that 1 mole of any substance contains 6.02×10²³ molecules. This simply implies that
1 mole of SO₃ = 6.02×10²³ molecules.
Recall,
1 mole of SO₃ = 80.063 g
Thus,
80.063 g of SO₃ = 6.02×10²³ molecules
With the above information, we can obtain the number of molecules in 5100 g of SO₃. This can be obtained as follow:
80.063 g of SO₃ = 6.02×10²³ molecules
Therefore,
5100 g of SO₃ [tex]= \frac{5100 * 6.02*10^{23} }{80.063}\\\\[/tex]
Therefore, 5100 g of SO₃ contains 3.83×10²⁵ molecules
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