Calculate the molality of acetone in an aqueous solution with a mole fraction for acetone of 0.241. Answer in units of m.

Respuesta :

Answer: The molality of solution is 17.6 mole/kg

Explanation:

Molality of a solution is defined as the number of moles of solute dissolved per kg of the solvent.

[tex]Molarity=\frac{n}{W_s}[/tex]

where,

n = moles of solute

[tex]W_s[/tex] = weight of solvent in kg

moles of acetone (solute) = 0.241

moles of water (solvent )= (1-0.241) = 0.759

mass of water (solvent )= [tex]moles\times {\text {Molar Mass}}=0.759\times 18=13.7g=0.0137kg[/tex]

Now put all the given values in the formula of molality, we get

[tex]Molality=\frac{0.241}{0.0137kg}=17.6mole/kg[/tex]

Therefore, the molality of solution is 17.6 mole/kg