Answer:
Ore 1 = 28 tons
Ore 2 = 8 tons
Cost = $3480
Explanation:
Complete solution is provided in attached pictures. The Objective function line is dragged to the lowest edge of feasible region to obtain the optimum solution of (28,8).
That is 28 tons of Ore type-1 and 8 tons of Ore Type-2 should be ordered to incur minimum cost of $3480.