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Dave has several golf balls in his golf bag. Seven of them are brand A, 9 are brand B, and 2 are brand C. He reaches into the bag and randomly selects one golf ball, then he selects a second one without replacing the first one. What is the probability that the first one is a brand A golf ball and the second one is a brand C golf ball?

Respuesta :

Answer:

Explanation:

Given

bag contain

7 balls of brand A

9 balls of brand B

2 balls of brand C

Dave randomly select the a ball and then a second ball without replacement of first ball

Probability that first ball is A golf ball [tex]P(A)=\frac{7}{18}[/tex]

Probability that second ball is of brand C [tex]P(C)=\frac{2}{17}[/tex]

Probability that the first one is a brand A golf ball and the second one is a brand C golf ball[tex]=P(A)\times P(B)[/tex]

[tex]=\frac{7}{18}\times \frac{2}{17}=\frac{7\times 2}{18\times 17}=\frac{14}{306}=0.045[/tex]

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