The second angle of a triangle is 50° less than the first angle the third angle is 40° less than the first angle find the measurements of all three angles

Respuesta :

Answer:

First angle = [tex]90^{\circ}[/tex]

Secomd angle  = [tex]40^{\circ}[/tex]

Thirsd angle   =  [tex]50^{\circ}[/tex]

Step-by-step explanation:

Let  the first angle be x------------(1)

Then the second angle is 50° less than the first angle

Then the second angle will be x -50------------(2)

The third angle is 40° less than the first angle

Then the angle will be x - 40------------(3)

We know that, according to angle sum property , the sum of all the three angle will be 180 degrees

So adding all the 3 angles,

[tex]x + (x -50^{\circ}) +(x -40 ^{\circ}) = 180^{\circ}[/tex]

[tex]x + x -50^{\circ} +x -40 ^{\circ} = 180^{\circ}[/tex]

[tex]3x -90^{\circ} = 180^{\circ}[/tex]

[tex]3x = 180^{\circ} +90^{\circ}[/tex]

[tex]3x = 270^{\circ}[/tex]

[tex]x = \frac{270^{\circ}}{3}[/tex]

[tex]x = 90^{\circ}[/tex]

Now the second angle is

=> [tex]x -50^{\circ}[/tex]

=> [tex]90 ^{\circ} -50 ^{\circ}[/tex]

=> [tex]40^{\circ}[/tex]

The Third angle is

=> [tex]x- 40^{\circ}[/tex]

=>[tex]90^{\circ} - 40^{\circ}[/tex]

=> [tex]50^{\circ}[/tex]