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A small electronic device is rated at 0.16 W when connected to 115 V. What is the resistance of this device?

Respuesta :

asuwafoh

Answer:

150156.25 Ω

Explanation:

Resistance: This can be defined as the opposition to the flow of electric current in a circuit. The S.I unit of resistance is Ohm's (Ω)

The expression for resistance is given as

P = V²/R................ equation 1

Where P = power, V = Voltage, R = Resistance.

Making R the subject of the equation,

R = V²/P.................. Equation 2

Given: V = 115 V , P = 0.16 W.

Substitute into equation 2

R = 155²/0.16

R = 150156.25 Ω

Hence,

The resistance = 150156.25 Ω

stigawithfun

Answer:

82.656 KΩ

Explanation:

The power rating (P) in a device is related to its voltage (V) and its resistance (R) as follows;

P = [tex]\frac{V^{2} }{R}[/tex]    ------------------------(i)

Where, according to the question;

P = 0.16W

V = 115V

R is unknown

Substitute the values of P and V into the equation (i);

=> P = [tex]\frac{V^{2} }{R}[/tex]

=> 0.16 = [tex]115^{2}[/tex] / R

Make R subject of the formula

=> R = [tex]\frac{115^{2} }{0.16}[/tex]

=> R = 13225 / 0.16

=> R = 82656.25Ω

=> R = 82.656KΩ

The resistance of the device is R = 82.656KΩ

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