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Assume you are working with a standard deck of 52 cards. There are 13 cards (2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king, and ace) in each of four suits (clubs, diamonds, hearts, and spades). What is P(9 ∪ Queen) if you draw one card?
0
2/13
7/52
4/13

Respuesta :

sam4040

Answer:

[tex]P(9\cup queen)=\frac{2}{13}[/tex]

Step-by-step explanation:

Total number of cards[tex]=52[/tex]

Total cards of [tex]9[/tex][tex]=4(1\ club,1\ diamond,1\ heart,1\ spades)[/tex]

Total cards of Queen[tex]=4(1\ club,1\ diamond,1\ heart,1\ spades)[/tex]

Total number of elements in [tex]9\cup Queen[/tex][tex]=8[/tex]

[tex]P(9\cup queen)=\frac{elements\ in\ 9\cup queen}{Total\ number\ of\ elements}\\\\P(9\cup queen)=\frac{8}{52}=\frac{2}{13}[/tex]

The value of P(9 ∪ Queen) if you draw one card is [tex]2\div 13[/tex] and this can be determined by using the given data.

Given :

  • You are working with a standard deck of 52 cards.
  • There are 13 cards (2, 3, 4, 5, 6, 7, 8, 9, 10, jack, queen, king, and ace) in each of four suits (clubs, diamonds, hearts, and spades).

The following calculation can be used to determine P(9 ∪ Queen) if you draw one card:

Given that the total number of cards = 52

There are total cards of 9 are 4 that is one club, one diamond, one heart, and one spade.

The total cards of Queen are 4 that is one club, one diamond, one heart, and one spade.

So, the number of elements in [tex]\rm (9\cup Queen)[/tex] is 8.

[tex]\rm P(9\cup Queen )=\dfrac{Elements \; in \; 9\cup Queen}{Total \; number \; of \; elements}[/tex]

[tex]\rm P(9\cup Queen )=\dfrac{8}{52}[/tex]

[tex]\rm P(9\cup Queen )=\dfrac{2}{13}[/tex]

For more information, refer to the link given below:

https://brainly.com/question/22687297

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