Answer:
Bromine displaced iodide to form iodine
Explanation:
In this experiment, liquid bromine was allowed to react with a solution of potassium iodide.
Initially, we had a colorless [tex]KI[/tex] solution which was mixed with light orange [tex]Br_2[/tex]. If we add a light orange solution to a colorless solution, liquid bromine will get diluted and we'll see a slight decrease in its color intensity, however, if no reaction takes place, no color change will occur.
In the experiment, however, we examine a formation of a deep brown solution. Remember that iodine solution would form a brown solution.
As a result, bromine displaced iodide anion from potassium iodide:
[tex]2~KI~(aq) + Br_2~ (l)\rightarrow 2~KBr~(aq) + I_2~(aq)[/tex]
