Respuesta :
Answer:
x = 0.81 m
Explanation:
given,
spring constant, k = 769 N/m
Potential energy of the spring = 250 J
distance of spring compression = ?
using conservation of energy
potential energy will equal to the spring energy
[tex]PE = \dfrac{1}{2}kx^2[/tex]
[tex]250= \dfrac{1}{2}\times 769\times x^2[/tex]
x² = 0.650
x = 0.81 m
Hence, the spring is compressed to 0.81 m
The energy stored in the body in a rest state is called potential energy.
There are two types of mechanical energy. The mechanical energy is consist of the following:-
- Kinetic energy
- Potential energy
According to the question, the solution is:-
The formula we used is[tex]PE= \frac{1}{2}kx^{2}[/tex]
After putting the value the equation is stated as follows:-
[tex]250 =\frac{1}{2} *769*x^{2}[/tex]
Hence the [tex]x^{2}[/tex] is equal to:-
[tex]x^{2} = 651\\x= 0.81[/tex]m
The spring compressed in 0.81m
For more information, refer to the link:-
https://brainly.com/question/13784481
