One day in October 2005, you could exchange $3 for about 2.5 euros. How many dollars would you have needed to get 8 euros?

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16-01-2020
Mathematics

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One day in October 2005, you could exchange $3 for about 2.5 euros. How many dollars would you have needed to get 8 euros?

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princedx1 princedx1 · Answer 1 · 2020-01-16T23:53:48+01:00

princedx1 princedx1

16-01-2020

10 because 3$ times two is 5 dollars in euros, and 4 dollars is 3 dollars in euros. Therefore if you add 6 and four together you get a total of 10 dollars

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